py2exe __file__ is not defined

py2exe 沒有 __file__ 可以使用,替代解法:

Here is the py2exe documentation reference and here are the relevant items:

  • sys.executable is set to the full pathname of the exe-file.
  • The first item in sys.argv is the full pathname of the executable, the rest are the command line arguments.
  • sys.frozen only exists in the executable. It is set to “console_exe” for a console executable, to “windows_exe” for a console-less gui executable, and to “dll” for a inprocess dll server.
  • __file__ is not defined (you might want to use sys.argv[0] instead)

It is not apparent from those docs whether “the exe-file” and “the executable” are the same thing, and thus whether sys.executable and sys.argv[0] are the same thing. Looking at code that worked for both and py2exe_executable.exe last time I had to do this, I find something like:

if hasattr(sys, 'frozen'):
    basis = sys.executable
    basis = sys.argv[0]
required_folder = os.path.split(basis)[0]

As I say that worked, but I don’t recall why I thought that was necessary instead of just using sys.argv[0].

Using only basis was adequate for the job in hand (read files in that directory). For a more permanent record, split something like os.path.realpath(basis).

Update Actually did a test; beats guesswork and armchair pontification 🙂

Summary: Ignore sys.frozen, ignore sys.executable, go with sys.argv[0] unconditionally.


=== ===

# coding: ascii
import sys, os.path
print 'sys has frozen:', hasattr(sys, 'frozen')
print 'using sys.executable:', repr(os.path.dirname(os.path.realpath(sys.executable)))
print 'using sys.argv[0]:',    repr(os.path.dirname(os.path.realpath(sys.argv[0]   )))

=== ===

from distutils.core import setup
import py2exe

=== results ===

sys has frozen: False
using sys.executable: 'C:\\python26'
using sys.argv[0]: 'C:\\junk\\so\\py2exe' # where lives

sys has frozen: True
using sys.executable: 'C:\\junk\\so\\py2exe\\dist'
using sys.argv[0]: 'C:\\junk\\so\\py2exe\\dist' # where foo.exe lives




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