[Python] How to verify element present or visible in selenium

要如何知道某一個物件在網頁裡的狀態？

sample code how to verify element

1. ispresent
   
2. isvisible
   
3. isenable
   
4. textpresent
   

in Selenium WebDrvier using Java

---

To check Element Present:

if(driver.findElements(By.xpath("value")).size() != 0){
 System.out.println("Element is Present");
 }else{
 System.out.println("Element is Absent");
 }

Or

if(driver.findElement(By.xpath("value"))!= null){
 System.out.println("Element is Present");
 }else{
 System.out.println("Element is Absent");
 }

To check Visible:

if( driver.findElement(By.cssSelector("a > font")).isDisplayed()){
 System.out.println("Element is Visible");
 }else{
 System.out.println("Element is InVisible");
 }

To check Enable:

if( driver.findElement(By.cssSelector("a > font")).isEnabled()){
 System.out.println("Element is Enable");
 }else{
 System.out.println("Element is Disabled");
 }

To check text present

if(driver.getPageSource().contains("Text to check")){

System.out.println("Text is present");

}else{

System.out.println("Text is absent");

}

---

上面是 java 的版本，要改成python 就改用 is_displayed() 就可以了。

範例：

def login():
  user_elements = browser.find_elements_by_xpath('//input[contains(@name, "user")]')
  for user in user_elements:
   if user.is_displayed():
    if user.is_enabled():
     user.send_keys(username)
     pass_elements = browser.find_elements_by_xpath('//input[contains(@name, "pass")]')
     for passw in pass_elements:
      if passw.is_displayed():
        if passw.is_enabled():
         passw.clear()
         passw.send_keys(password + Keys.RETURN)   #Crashes here
         time.sleep(4)
         return